Authors: Rainer Mandel
Publish Date: 2015/10/24
Volume: 54, Issue: 4, Pages: 3905-3925
Abstract
Let A=00B=10 and theta 1=theta 2in 0pi /2 Then the Dirichlet problem 1 has infinitely many axially symmetric solutions gamma 1j and infinitely many axially nonsymmetric solutions gamma 2j satisfying Wgamma 1jWgamma 2jrightarrow infty as jrightarrow infty The existence of infinitely many axially symmetric solutions gamma 1j jin mathbb N 0 of 1 follows from Theorem 4 Corollary 1 and the fact that for every eta in 1+1 and every jin mathbb N 0 a solution of 32 is given by sigma 1=1sigma 2=1z=barz=eta cos theta 11/2 The formula for a and W from Theorem 4 implies that these solutions satisfy Wgamma 1jrightarrow infty as jrightarrow infty and sigma 1mathrmcn1z+sigma 2mathrmcn1barz=0 implies that gamma 1j is axially symmetric
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